0=x^2-4x+20

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Solution for 0=x^2-4x+20 equation: 



0=x^2-4x+20

We move all terms to the left:

0-(x^2-4x+20)=0

We add all the numbers together, and all the variables

-(x^2-4x+20)=0

We get rid of parentheses

-x^2+4x-20=0

We add all the numbers together, and all the variables

-1x^2+4x-20=0

a = -1; b = 4; c = -20;
Δ = b2-4ac
Δ = 42-4·(-1)·(-20)
Δ = -64
Delta is less than zero, so there is no solution for the equation

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